\u4e3b\u8981\u662f\u53cc\u6307\u9488\u548c\u6ed1\u52a8\u6307\u9488\u6280\u5de7<\/p>\n
\u53cc\u6307\u9488\u4e00\u822c\u7528\u4e8e\u5e8f\u5217\u95ee\u9898\uff0c\u5176\u5206\u914d\u4e24\u4e2a\u6307\u9488\u6765\u5b8c\u6210\u7b97\u6cd5\u4efb\u52a1\uff0c\u53ef\u5c06\u95ee\u9898\u4f18\u5316\u4e3a\u7ebf\u6027\u590d\u6742\u5ea6<\/p>\n
\u5e38\u89c1\u573a\u666f\u53ca\u5e94\u7528\u5982\u4e0b<\/p>\n
\u6700\u7b80\u5355\u7684\u505a\u6cd5\u662f\u628a\u4e24\u4e2a\u5e8f\u5217\u8bfb\u5165\u540c\u4e00\u4e2avector\uff0c\u8c03sort()\u51fd\u6570\uff0c\u7d22\u5f15$\\scriptsize \\lfloor N\/2\\rfloor $\u5373\u53ef\uff0c\u590d\u6742\u5ea6 $\\scriptsize O(nlogn)$
\n\u9274\u4e8e\u672c\u9898\u6837\u4f8b\u89c4\u6a21 $\\scriptsize \\sim 10^5$\uff0c\u8003\u8651\u7c7b\u4f3c\u5f52\u5e76\u6709\u5e8f\u5e8f\u5217\u7684 $\\scriptsize O(n)$ \u53cc\u6307\u9488\u65b9\u6cd5
\n\u57fa\u4e8e\u6709\u5e8f\u5217\u8868\u7684\u6027\u8d28\uff0c\u8fd8\u53ef\u7528\u4e8c\u5206\u65b9\u6cd5\u4f18\u5316\u81f3 $\\scriptsize O(logn)$\uff0c\u5c06\u5728\u4e8c\u5206\u6587\u7ae0\u4e2d\u8bb2\u89e3<\/p>\n
(\u02c9\ufe43\u02c9)<\/strong> Q\uff1a\u4e24\u4e2a\u6570\u7ec4\u90fd\u53ef\u80fd\u4f1a\u4f18\u5148\u88ab\u904d\u5386\u5b8c\u672b\u5c3e\uff0c\u8fd9\u79cd\u60c5\u51b5\u600e\u4e48\u5904\u7406\uff1f<\/p>\n (\u2032\uff5e`\u25cf)<\/strong> A\uff1a\u4efb\u4e00\u6307\u9488\u5148\u5230\u8fbe\u672b\u5c3e\uff0c\u540e\u7eed\u90fd\u53ea\u80fd\u4ece\u53e6\u4e00\u5e8f\u5217\u7ee7\u7eed\u9012\u589e\u3002\u57fa\u4e8e\u6b64\u60f3\u6cd5\uff0c\u4f18\u5148\u5904\u7406\u5230\u8fbe\u672b\u5c3eS[n-1]\u7684\u60c5\u51b5\uff1a\u6392\u9664\u5230\u8fbe\u672b\u5c3e\u60c5\u51b5\uff0c\u6b64\u65f6\u4e24\u6307\u9488\u7684\u9012\u589e\u4fdd\u8bc1\u5728\u5408\u6cd5\u8303\u56f4\uff0c\u5c31\u53ef\u4ee5\u7c7b\u4f3c\u5408\u5e76\u6709\u5e8f\u5e8f\u5217\u64cd\u4f5c\u5566<\/p>\n (?\u2200?)<\/strong> Q\uff1a\u5982\u679cp1,p2\u521d\u59cb\u5316\u4e3a0\uff0c\u5047\u5b9aS1<S2\uff0c\u5728\u521a\u521a\u904d\u5386\u5b8c\u6bd5S1\u4eceS2\u5f00\u59cb\u65f6\uff0cp2++\u4f1a\u591a\u52a0\u4e00\u6b21\uff0c\u4e0d\u52a0\u53c8\u65e0\u6cd5\u5411\u540e\u7ee7\u7eed\u600e\u4e48\u529e\uff1f<\/p>\n (-\u03c9- )<\/strong> A\uff1a\u547c~\u52a8\u4e0b\u5c0f\u8111\u7b4b\uff0c\u8ba9\u6307\u9488\u4ece -1\u5f00\u59cb\u9012\u589e<\/strong> \uff0c\u662f\u4e0d\u662f\u5c31\u80fd\u7edf\u4e00\u5566\uff1f\u76f8\u5e94\u5730\uff0c\u5728\u6bd4\u8f83\u5143\u7d20\u65f6\uff0c\u5fc5\u987b\u6bd4\u8f83\u7684\u662f S1[p1+1]\u548cS2[p2+1]<\/strong>\u3002\u5f53\u7136\u4e5f\u6709\u4e2a\u6307\u9488\u4ece0\u5f00\u59cb\u7684\u597d\u65b9\u6cd5\uff0c\u5c31\u662f\u8ba9\u7ed3\u5c3eS[n]=MAX_INT\uff0c\u8fd9\u6837\u4e5f\u8fbe\u5230\u4e86\u7edf\u4e00<\/p>\n (-_-\u3002)???<\/strong> Q\uff1a\u600e\u4e48\u5224\u5b9a\u7b97\u6cd5\u7ed3\u675f\uff1f\u600e\u4e48\u5224\u5b9a\u4e2d\u4f4d\u6570\u6700\u540e\u662fS1[p1]\u8fd8\u662fS2[p2]\uff1f<\/p>\n (`\uff65\u03c9\uff65\u2032)\u309e<\/strong> A\uff1a\u5faa\u73af\u6b21\u6570\u5b9e\u9645\u5c31\u662f\u6307\u9488\u79fb\u52a8\u7684\u6b21\u6570<\/strong>\uff0c\u5c06\u4e24\u4e2a\u5e8f\u5217\u770b\u4e3a\u4e00\u4e2a\u5e8f\u5217\uff0c\u4e2d\u4f4d\u6570\u4e0b\u6807\u4e3a $\\scriptsize (\\frac{N-1}{2})=(\\frac{n1+n2-1}{2})$\uff0c\u6307\u9488\u4ece $\\scriptsize (-1)\u2192(\\frac{n1 + n2 – 1}{2})$ \u5f97\u5faa\u73af\u6b21\u6570\u4e3a $\\scriptsize \\frac{n1 + n2 + 1}{2}$\uff1b\u6700\u540e\u4e00\u6b21\u4fee\u6539\u540e\u7684\u6307\u9488\u5fc5\u7136\u662f\u6240\u6c42\u4e2d\u4f4d\u6570\u4f4d\u7f6e\uff0c\u6bcf\u6b21\u4fee\u6539\u6307\u9488\u4f7f\u7528\u53d8\u91cf\u4fdd\u5b58\u8d77\u6765\u5c31OK\u4e86\u3002\u4f7f\u75280\u5f00\u59cb\u65b9\u6848\u53ef\u4ee5\u51cf\u5c11\u8bbf\u5b58\uff1a\u4e2d\u4f4d\u6570\u5b9e\u9645\u662f\u7ed3\u675f\u65f6p1\u548cp2\u6240\u6307\u7684\u5143\u7d20\u4e2d\u66f4\u5c0f\u7684\u90a3\u4e2a<\/p>\n (\u25cf?\u03c9?\u25cf)<\/strong> Q\uff1a\u9898\u76ee\u52a0\u9ed1\u7684long int\uff0c\u6211\u8981\u8bbe\u7f6elong\u7c7b\u578b\u5417\uff1f<\/p>\n (\u25cd\u2019\u0c6a`\u25cd)\uff89\uff9e<\/strong> A\uff1ag++\u4e2dlong int\u4e0eint\u540c\u88ab\u7f16\u8bd1\u4e3a4B=32bit\uff0cint\u5373\u53ef<\/p>\n \u5173\u4e8e\u6b64\u95ee\u9898\u53ca\u53d8\u5f0f\u89e3\u6cd5\u5982\u4e0b<\/p>\n \u548c\u4e3aS\u7684\u4e24\u6570<\/strong> \u8fde\u7eed\u548cS\u7684\u5b50\u5e8f\u5217<\/strong> \u6ed1\u52a8\u6307\u9488\u7684\u601d\u60f3\u662f\u4e0d\u8ba1\u7b97\u5177\u4f53\u503c\uff0c\u53ea\u7ed9\u8fb9\u754c\u5e76\u6309\u7167\u4e00\u5b9a\u89c4\u5f8b\u79fb\u52a8<\/p>\n \u786e\u5b9a\u87ba\u65cb\u65b9\u5411\u987a\u5e8f\u662f\u201c\u53f3\u4e0b\u5de6\u4e0a\u201d\uff1a \u786e\u5b9a\u4f55\u65f6\u6362\u65b9\u5411\uff1a\u6bcf\u68c0\u6d4b\u5230\u8fb9\u754c\u6362\u4e0b\u4e00\u65b9\u5411 \u5173\u4e8e\u8fb9\u754c\u7684\u786e\u5b9a\uff1a Q\uff1a\u5b9e\u73b0\u2460\u6211\u7684while\u5168\u5199\u7684\u662fif\uff0c\u611f\u89c9\u6ca1\u4ec0\u4e48\u95ee\u9898\u554a<\/p>\n A\uff1a\u4e0d\u575a\u6301\u4e00\u4e2a\u65b9\u5411\u7684\u8bdd\uff0c\u4f1a\u5728\u4e2d\u9014\u5339\u914d\u5230\u7b26\u5408\u6761\u4ef6\u7684\u5176\u4ed6\u65b9\u5411\uff0c\u5982\u4e0b\u6837\u4f8b\u4e00\u76f4\u523053\u8fd8\u8fd0\u884c\u6b63\u5e38\uff0c\u4f46\u662f\u4e0b\u4e00\u4e2a\u5339\u914d\u7684\u5c31\u662f20\u4e86\u3002\u6240\u4ee5\u6bcf\u5230\u8fb9\u754c\u624d\u80fd\u53d8\u66f4\u65b9\u5411\uff0c\u53d8\u66f4\u540e\u76f4\u5230\u4e0b\u4e00\u4e2a\u8fb9\u754c\u524d\u90fd\u8981\u4fdd\u6301\u65b9\u5411<\/p>\n Q\uff1a\u554a\u2026\u2026\u6211\u7684\u903b\u8f91\u5b8c\u5168\u6ca1\u95ee\u9898\uff0c\u4f46\u8fd8\u662f\u6709\u6d4b\u8bd5\u70b9\u9519\u8bef\uff1f<\/p>\n A\uff1a\u770b\u770b\u4f60\u7684\u6570\u636e\u6ee1\u4e0d\u6ee1\u8db3 $\\scriptsize m\\geqslant n$\uff0c\u9898\u4e2d\u7740\u91cd\u8981\u6c42\u5566\u3002\u9898\u610f\u7684\u6700\u5c0f\u5dee\u8ddd\u662f\u6574\u6570\u7b97\u6570\u5e73\u65b9\u6839\uff0c\u627e\u5230 $\\scriptsize m=\\lfloor\\sqrt N\\rfloor$\uff0c\u82e5\u6709\u6574\u6570\u7b97\u672f\u5e73\u65b9\u6839\uff0cm\u5373\u6240\u6c42\uff1b\u65e0\u6574\u6570\u7b97\u6570\u5e73\u65b9\u6839\u65f6\u9012\u589e\u5bfb\u627e\u7b2c\u4e00\u4e2a\u53ef\u88ab\u6574\u9664\u7684m\uff0c\u6240\u5f97\u4e24\u56e0\u5b50\u5dee\u503c\u6700\u5c0f\u3002\u9012\u51cf\u6c42n\u4e5f\u53ef\uff0c\u5c24\u5176\u662f\u5927\u8d28\u6570\u6837\u4f8b\u53ef\u51cf\u5c11\u904d\u5386\u6b21\u6570\uff0c\u4f46\u8981\u6ce8\u610f\u6c42n\u65f6\u9700\u8981\u5224\u522b\u5e76\u4fdd\u8bc1\u4e0em\u7684\u5927\u5c0f\u5173\u7cfb<\/p>\n \u7efc\u8ff0 \u4e3b\u8981\u662f\u53cc\u6307\u9488\u548c\u6ed1\u52a8\u6307\u9488\u6280\u5de7 \u53cc\u6307\u9488 \u53cc\u6307\u9488\u4e00\u822c\u7528\u4e8e\u5e8f\u5217\u95ee\u9898\uff0c\u5176\u5206\u914d\u4e24\u4e2a\u6307\u9488\u6765\u5b8c\u6210\u7b97\u6cd5\u4efb\u52a1\uff0c\u53ef\u5c06\u95ee\u9898\u4f18\u5316\u4e3a … <\/p>\n
\n#include <iostream>\nusing namespace std;\n\nconst int maxn = 200001;\nint s1[maxn], s2[maxn];\n\nint main() {\n int n1, n2;\n scanf(\"%d\", &n1);\n for (int i = 0; i < n1; i++)\n scanf(\"%d\", &s1[i]);\n scanf(\"%d\", &n2);\n for (int i = 0; i < n2; i++)\n scanf(\"%d\", &s2[i]);\n\n int p1 = -1, p2 = -1, cnt = (n1 + n2 + 1) \/ 2, m;\n while (cnt--) {\n if (p1 == n1 - 1) { m = s2[++p2]; continue; }\n if (p2 == n2 - 1) { m = s1[++p1]; continue; }\n if (s1[p1 + 1] < s2[p2 + 1]) m = s1[++p1];\n else m = s2[++p2];\n }\n printf(\"%d\\n\", m);\n return 0;\n}\n<\/code><\/pre>\nPAT-A1048 \u6392\u5e8f\u6570\u7ec4\u8fde\u7eed\u548c\u95ee\u9898<\/h3>\n
\n\u7ed9\u5b9a\u4e24\u6307\u9488\uff1a$\\scriptsize small$ \u4ece0\u5f00\u59cb\u540e\u5411\u904d\u5386\uff0c$\\scriptsize large$ \u4eceN-1\u5f00\u59cb\u524d\u5411\u904d\u5386
\n\u2460 \u5148\u5361\u53f3\u8fb9\u754c\u786e\u5b9a\u6700\u5927\u80fd\u53d6\u7684\u6570\uff1a\u6b64\u65f6 $\\scriptsize small$ \u662f\u6700\u5c0f\u7684\uff0c\u548c $\\scriptsize sum \\gt small+large$\uff0c\u4e00\u5b9a\u662f $\\scriptsize large$ \u8fc7\u5927\u8981\u5411\u5c0f\u8c03\u6574\uff0c\u5426\u5219\u65e0\u89e3\u3002
\n\u2461 \u518d\u5361\u5de6\u8fb9\u754c\u6700\u5c0f\u53ef\u53d6\u7684\u6570\uff1a\u6b64\u65f6 $\\scriptsize large$ \u5df2\u7ecf\u662f\u6700\u5927\u4e86\uff0c\u5982\u679c\u8fd9\u4e2a\u65f6\u5019 $\\scriptsize sum \\lt small+large$\uff0c\u8bf4\u660e $\\scriptsize small$ \u8fd8\u4e0d\u591f\u5927\u8981\u5411\u5927\u8c03\u6574\uff0c\u5426\u5219\u65e0\u89e3\u3002
\n\u2462 $\\scriptsize sum = small+large$\uff0c\u6b64\u65f6\u627e\u5230\u6700\u5c0f $\\scriptsize small$ \u548c\u6700\u5927 $\\scriptsize large$ \u7684\u89e3\uff0c\u82e5\u8981\u5bfb\u627e\u6240\u6709\u89e3\uff0c\u53ea\u53ef\u80fd\u5728\u8303\u56f4 $\\scriptsize [small+1,large-1] \u4e2d$<\/p>\n
\n\u601d\u60f3\u540c\u4e0a
\n$\\scriptsize \\sum\\limits_{i=small}^{large}a[i] \\gt S$\uff0clarge–\uff0c
\n$\\scriptsize \\sum\\limits_{i=small}^{large}a[i] \\lt S$\uff0clarge++
\n$\\scriptsize \\sum\\limits_{i=small}^{large}a[i] == S$\uff0csmall++\uff0clarge–<\/p>\n#include <iostream>\n#include <algorithm>\n#include <bits\/stdc++.h>\nusing namespace std;\n\nconst int maxn = 100001;\nint coins[maxn];\n\nint main() {\n int N, M;\n scanf(\"%d %d\", &N, &M);\n memset(coins, 0, sizeof(coins));\n for (int i = 0; i < N; i++)\n scanf(\"%d\", &coins[i]);\n\n sort(coins, coins + N);\n int small = 0, large = N - 1;\n while (small < large) {\n if (coins[small] + coins[large] > M)\n large--;\n else if (coins[small] + coins[large] < M)\n small++;\n else {\n printf(\"%d %d\\n\", coins[small], coins[large]);\n return 0;\n }\n }\n\n printf(\"No Solution\\n\");\n return 0;\n}\n<\/code><\/pre>\n\u6ed1\u52a8\u6307\u9488<\/h2>\n
PAT-A1105 \u87ba\u65cb\u77e9\u9635<\/h3>\n
\n\u5b9e\u73b0\u2460 \u5de6\u53f3\u52a0\u51cfcol\uff0c\u4e0a\u4e0b\u52a0\u51cfrow
\n\u5b9e\u73b0\u2461 \u4e0a\u4e0b\u5de6\u53f3\u8bb0\u5165\u6570\u7ec4 $\\scriptsize D=[[0,1],[1,0],[0,-1],[-1,0]]$<\/p>\n
\n\u5b9e\u73b0\u2460\u901a\u8fc7while\u4fdd\u6301\u6bcf\u4e2a\u65b9\u5411\u4e0d\u53d8\u76f4\u5230\u4e0b\u4e00\u8fb9\u754c\uff0c\u9632\u6b62\u4e2d\u9014\u66f4\u6539\u65b9\u5411
\n\u5b9e\u73b0\u2461\u68c0\u6d4b\u5230\u8fb9\u754c\u53d8\u66f4\u65b9\u5411 $\\scriptsize row + D[(++i)\\%4][0]\uff0ccol+D[(++i)\\%4][1]$<\/p>\n
\n\u2460 \u8bbf\u95ee\u6807\u8bb0\uff1a\u4e0d\u8d85\u6570\u7ec4\u8fb9\u754c\u3001\u4e0d\u8986\u76d6\u5df2\u8bbf\u95ee\u5e76\u6807\u8bb0\u7684\u5143\u7d20
\n\u2461 \u9010\u5c42\u5185\u5939\uff1a\u4e0d\u8d85\u8fc7\u5f53\u8f6e\u56db\u4e2a\u6700\u5916\u5c42\u53f7\u8bb0\u5f55\u53d8\u91cf<\/p>\n
\n98 95 93\n42 37 81\n53 20 76\n58 60 76\n<\/code><\/pre>\n
\n#include <iostream>\n#include <algorithm>\n#include <bits\/stdc++.h>\nusing namespace std;\nint num[100001];\n\nint main() {\n int N, m = 1, n;\n scanf(\"%d\", &N);\n for (int i = 0; i < N; i++)\n scanf(\"%d\", &num[i]);\n sort(num, num + N, greater<int>());\n\n for (; m * m < N; m++);\n while(N % m != 0) m++;\n n = N \/ m;\n\n int ans[m][n];\n memset(ans, -1, sizeof(ans));\n int row = 0, col = -1, p = 0;\n while (p < N) {\n while (col < n - 1 && ans[row][col + 1] == -1) ans[row][++col] = num[p++];\n while (row < m - 1 && ans[row + 1][col] == -1) ans[++row][col] = num[p++];\n while (col > 0 && ans[row][col - 1] == -1) ans[row][--col] = num[p++];\n while (row > 0 && ans[row - 1][col] == -1) ans[--row][col] = num[p++];\n }\n\n for (int i = 0; i < m; i++)\n for (int j = 0; j < n; j++)\n if (j < n - 1) printf(\"%d \", ans[i][j]);\n else printf(\"%d\\n\", ans[i][j]);\n\n return 0;\n}\n<\/code><\/pre>\n","protected":false},"excerpt":{"rendered":"